If a quadratic equation ... value of 0 and substituting \(x = 0\) into the equation \(y = ax^2 + bx + c\) gives \(y = c\). a) The constant term is -2, so the y-intercept is (0, -2) b) The constant ...

If a quadratic equation ... value of 0 and substituting \(x = 0\) into the equation \(y = ax^2 + bx + c\) gives \(y = c\). a) The constant term is -2, so the y-intercept is (0, -2) b) The constant ...

If a quadratic equation ... value of 0 and substituting \(x = 0\) into the equation \(y = ax^2 + bx + c\) gives \(y = c\). a) The constant term is -2, so the y-intercept is (0, -2) b) The constant ...

The coordinates of the turning point and the equation of the line of symmetry can be found by writing the quadratic expression ... point of the graph of \(y = x^2 – 6x + 4\) The coefficient ...