Draw the graph of \(y = 3x - 1\). If you recognise this as a straight line then just choose two ‘easy’ values of \(x\), work out the corresponding values of \(y\) and plot those points.

Find \(\ds \lim_{h\to 0}\frac{f(1+h)-f(1)}{h}\) where \(\ds f(x)=\frac{3x+1}{x-2}\text{.}\) What does the result in (a) tell you about the tangent line to the graph ...

The graphs above, \(y = 2x + 1\) and \(y = 2x - 2\) have the same gradient of 2. The lines are parallel. State the equation of a line that is parallel to \(y = 3x + 7\). To be parallel ...