If a quadratic equation ... value of 0 and substituting \(x = 0\) into the equation \(y = ax^2 + bx + c\) gives \(y = c\). a) The constant term is -2, so the y-intercept is (0, -2) b) The constant ...

For the parabola \(y=(x+6)(x-4)\) determine the coordinates and nature of its turning pont and the equation of the axis of symmetry. The roots are \(x=-6\) and \(x=4\). The aixs of the symmetry is ...

The coordinates of the turning point and the equation of the line of symmetry can be found by writing the quadratic expression ... point of the graph of \(y = x^2 – 6x + 4\) The coefficient ...